2(x^2-1)=-3(x^2+2)

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Solution for 2(x^2-1)=-3(x^2+2) equation: 



2(x^2-1)=-3(x^2+2)

We move all terms to the left:

2(x^2-1)-(-3(x^2+2))=0

We multiply parentheses

2x^2-(-3(x^2+2))-2=0



We calculate terms in parentheses: -(-3(x^2+2)), so:

-3(x^2+2)

We multiply parentheses

-3x^2-6

Back to the equation:

-(-3x^2-6)



We get rid of parentheses

2x^2+3x^2+6-2=0

We add all the numbers together, and all the variables

5x^2+4=0

a = 5; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·5·4
Δ = -80
Delta is less than zero, so there is no solution for the equation

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